Beautiful Math Problems, Infinite Vibes

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Algebra

Algebra Easy #linear

Find x if 2x + 5 = 19

Solve for the variable.

Solution

2x = 14 ⟹ x = 7.

AlgebraMedium#quadratic

Find the roots of x² − 5x + 6 = 0

Solve using factorization or quadratic formula.

Solution

(x−2)(x−3)=0 ⟹ x=2 or x=3.

AlgebraHard#systems

Solve the system:
{ 3x − 2y = 11,   4x + y = 17 }

Find ordered pair (x, y).

Solution

From 4x + y = 17 ⇒ y = 17−4x. Substitute: 3x − 2(17−4x) = 11 ⇒ 3x − 34 + 8x = 11 ⇒ 11x = 45 ⇒ x = 45/11. Then y = 17 − 4(45/11) = (187−180)/11 = 7/11.

AlgebraMedium#inequality

Solve the inequality: 5 − 2x < 3x + 10

Give your answer in interval notation.

Solution

5−2x < 3x+10 ⇒ −5 < 5x ⇒ x > −1. Interval: (−1, ∞).

AlgebraMedium#exponential

Solve for x: 3x+1 = 27

Express 27 as 3k.

Solution

27 = 3³ ⇒ x+1 = 3 ⇒ x = 2.

AlgebraHard#sequence

Sequence defined by a₁=2, an+1=3an+1. Find a closed form.

Solve the linear non-homogeneous recurrence.

Solution

Let bn=an+½ ⇒ bn+1=3bn, b₁=2.5 ⇒ bn=2.5·3^{n−1}. Hence an=2.5·3^{n−1}−½.

Geometry

GeometryEasy#area

Find the area of a triangle with base 10 and height 7.

Use A = ½bh.

Solution

A = ½·10·7 = 35.

GeometryMedium#circle

A right triangle has legs 6 and 8. Find the radius of the inscribed circle.

In a right triangle, r = (a + b − c)/2.

Solution

c=10. r=(6+8−10)/2=2.

GeometryHard#angles

In cyclic quadrilateral ABCD, ∠A = 70°, ∠B = 60°. Find ∠C.

Opposite angles in a cyclic quad sum to 180°.

Solution

∠C = 180° − ∠A = 110°.

GeometryMedium#distance

Distance between P(−3, 4) and Q(5, −2)?

Use √[(Δx)² + (Δy)²].

Solution

Δx=8, Δy=−6 ⇒ d=√(64+36)=√100=10.

Number Theory

Number TheoryEasy#gcd

Find gcd(84, 60).

Use prime factors or Euclid’s algorithm.

Solution

84=2²·3·7, 60=2²·3·5 ⇒ gcd=2²·3=12.

Number TheoryMedium#mod

Compute 7100 mod 5.

Reduce base modulo 5.

Solution

7≡2 (mod 5) ⇒ 2¹⁰⁰ ≡ 0? No. Since 2⁴≡1 ⇒ 100 multiple of 4 ⇒ ≡1.

Number TheoryHard#diophantine

Find all integer solutions of 14x + 21y = 7.

Simplify first.

Solution

Divide by 7 ⇒ 2x+3y=1 ⇒ x=1−3t, y=−1+2t for t∈ℤ.

Number TheoryMedium#digits

Smallest positive n such that sum of digits of 9n equals 9.

Use divisibility by 9 and simple search logic.

Solution

Let 9n have digit sum 9 ⇒ 9n ≡ 0 (mod 9) always; first is 9, digit sum 9 ⇒ n=1.

Calculus

CalculusEasy#derivative

Find d/dx (3x³ − 7x + 4).

Differentiate term by term.

Solution

9x² − 7.

CalculusMedium#chainrule

Compute d/dx (sin(x²)).

Apply chain rule.

Solution

cos(x²)·2x.

CalculusMedium#integral

Evaluate ∫ 2x·e^{x²} dx.

u-substitution recommended.

Solution

Let u=x² ⇒ du=2x dx ⇒ ∫ e^{u} du = e^{x²} + C.

CalculusHard#limit

Compute limx→0 (1 − cos x)/x².

Use Taylor or l’Hôpital.

Solution

≈ (1 − (1 − x²/2))/x² → 1/2.

Probability

ProbabilityEasy#coin

Flip a fair coin 3 times. Probability of exactly 2 heads?

Use binomial formula.

Solution

C(3,2)/2³ = 3/8.

ProbabilityMedium#cards

From a standard deck, probability the first card is a heart or an ace?

Use inclusion–exclusion.

Solution

P=13/52 + 4/52 − 1/52 = 16/52 = 4/13.

ProbabilityHard#expected

Roll a die until a 6 appears. Expected number of rolls?

Geometric distribution with p=1/6.

Solution

E = 1/p = 6.

ProbabilityMedium#bins

Ways to distribute 5 identical balls into 3 distinct boxes?

Stars and bars.

Solution

C(5+3−1, 3−1) = C(7,2) = 21.

Logic

LogicEasy#implication

Is (P ⇒ Q) logically equivalent to (¬P ∨ Q)?

State yes/no and justify.

Solution

Yes. Their truth tables coincide.

LogicMedium#pigeonhole

Show among 13 people, two share a birth month.

Name the principle used.

Solution

Pigeonhole principle with 12 months.

LogicHard#knights

On an island of knights (truth-tellers) and knaves (liars), A says “B is a knave.” B says “A and I are the same.” Who is who?

Consider cases for A.

Solution

If A is knight ⇒ B knave. But B says “same,” which would be false ⇒ consistent. So A knight, B knave.

LogicMedium#sets

Prove (A∩B)c = Ac ∪ Bc.

Name the law.

Solution

De Morgan’s law: x∉A∩B ⇔ (x∉A)∨(x∉B).